2*x^2+60*x-7200=0

Solution for 2*x^2+60*x-7200=0 equation:

2x^2+60x-7200=0

a = 2; b = 60; c = -7200;
Δ = b2-4ac
Δ = 602-4·2·(-7200)
Δ = 61200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61200}=\sqrt{3600*17}=\sqrt{3600}*\sqrt{17}=60\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{17}}{2*2}=\frac{-60-60\sqrt{17}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{17}}{2*2}=\frac{-60+60\sqrt{17}}{4}
$